- #1

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So I set it equal to zero to find the y-intercept

sin(x)=0(1+cos(x))

x= 0,∏ so the y-int: (0,0) and (0,∏)

To find the x intercept I would substitute 0 for x so,

sin(0)/(1+cos(0))=y

0/1+1=y

y=0 so the x-int: (0,0)

would that be right?

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- Thread starter vane92
- Start date

- #1

- 1

- 0

So I set it equal to zero to find the y-intercept

sin(x)=0(1+cos(x))

x= 0,∏ so the y-int: (0,0) and (0,∏)

To find the x intercept I would substitute 0 for x so,

sin(0)/(1+cos(0))=y

0/1+1=y

y=0 so the x-int: (0,0)

would that be right?

- #2

Infrared

Science Advisor

Gold Member

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Not only is it necessary for [itex] sin x [/itex] to be zero, but [itex] 1+ cos x [/itex] must also be nonzero. [itex] x = \pi [/itex] does not fulfill this second requirement.

Edit: This post should probably be in the Homework & Coursework Questions section.

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